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Mathematics 12 Online
OpenStudy (anonymous):

ind the probability for the experiment of drawing two marbles (without replacement) from a bag containing three green, four yellow, and five red marbles such that the marbles are different colors.

OpenStudy (anonymous):

47/66

OpenStudy (anonymous):

Thank you! Can you explain how you got that though?

OpenStudy (anonymous):

it occurs to me that you can calculate separately the probability of drawing a green marble, a red marble and a yellow marble, and then do the following: p(red)*p(yellow)+p(red)*p(green)+p(yellow)*p(green)

OpenStudy (turingtest):

I'm not sure I understand the question. Find the probability of drawing two of what kind of marble? You must have cut off more than just the f at the beginning.

OpenStudy (anonymous):

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