Question

WHAT IS THE EQUATION FOR THE LINE THAT IS PARRALEL TO THE GIVEN LINE AND THAT PASSES THROUGH A GIVEN POINT ?
Y=-3X+6;(0,1)

Answer 1

hey, where did you go?

Answer 2

Since you left all I will leave you is the formula:\[y-y_0=m(x-x_0)\]where\[(x_0,y_0)\]is your point in the problem.

Answer 3

HUH?

Answer 4

the formula for a line is:\[y-y_0=m(x-x_0)\]where\[(x_0,y_0)\]is your point in the problem.

m represents the slope.

It is the number next to the x.
What is m in your problem?

Answer 5

what is the slope of the line\[y=-3x+6\]I just said the slope is the number next to the x...

Answer 6

if a line l1 is parallel to another line l2, then l1 &l2 have same slope.
so as per the line equation => y=mx +c (where m is the slope and c is the constant)
so the l2 => y=3x+c
to find 'c' we need to substitute the given points to it
1=3(0)+c
=>c=1
so your required line is =>y=3x+1

Answer 7

Since it is parallel, the slope is -3

y = -3x + b

We know that (0, 1) implies that x=0 and y=1

1 = -3 + b

Now solving for b we have

b = 4

Therefore,

y = -3x + 4

Answer 8

There is a shortcut which could reduce this problem into much easier things.

Answer 9

i GOT Y=3X+1
SO I WENT WITH DHASNI ON THIS ON

Answer 10

E

Answer 11

Hey FFM,
everybody's wrong, right?

Answer 12

any line can be written as y=mx+c.
A line parallel to other line have the same slope as the parallel line.
And c can be found out by substituting the given point in thre obtained equation say here y=3x+c. Now x=0 and y=1 gives c=1.And so the required equation is
y=3x+1