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Mathematics 9 Online
OpenStudy (anonymous):

Find x > 3 such that ln(x) < x^(0.1)

myininaya (myininaya):

did you try graphing both ln(x) and x^(.1)

myininaya (myininaya):

try a value btw x=0 and x=3

OpenStudy (anonymous):

x^0.1 will be greatly large however if rearrange them to e^x^0.1<x this is true as well

myininaya (myininaya):

not including 0 of course

myininaya (myininaya):

but you can include 3

myininaya (myininaya):

so to be more exact 0<x<=3

OpenStudy (anonymous):

but if rearrange them e^x^0.1-x<0 this is true because e^(Positive number)= big number thus, it can be greater or equal to 3

OpenStudy (mertsj):

I don't think there is a solution because a condition of the problem is that x is greater than 3

myininaya (myininaya):

there is no x>3 such that inequality holds since my inequality is the only one that satisfies the inequality you gave

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