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Find x > 3 such that ln(x) < x^(0.1)
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did you try graphing both ln(x) and x^(.1)
try a value btw x=0 and x=3
x^0.1 will be greatly large however if rearrange them to e^x^0.1<x this is true as well
not including 0 of course
but you can include 3
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so to be more exact 0<x<=3
but if rearrange them e^x^0.1-x<0 this is true because e^(Positive number)= big number thus, it can be greater or equal to 3
I don't think there is a solution because a condition of the problem is that x is greater than 3
there is no x>3 such that inequality holds since my inequality is the only one that satisfies the inequality you gave
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