Question

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

-2y^2 - 8y = -6

Answer 1

first step:\[-2y^2-8y+6=0,\]\[y^2+4y-3=0.\]

Answer 2

Since it is asking to use the quadratic formula
figure out the variables so
a = -2 b = -8 and c = 6

you should have a copy of the formula to go along with this question I recommend memorizing it.

First thing you should do is solve what is under the radical if you end up with a negative it there are no solutions.

Remember

-b
=
-(-8) = 8 (a negative times a negative gives a positive)