For the function below, find the vertex, axis of symmetry, maximum or minimum value, and the graph of the function.

f(x)=(x^2/2) + 2x +1

Question

For the function below, find the vertex, axis of symmetry, maximum or minimum value, and the graph of the function.

f(x)=(x^2/2) + 2x +1

anonymous · Answer

$$f(x) = x^2/2 +2x +1$$

to find the vertex, I find (h,k)

mertsj · Answer

The x coordinate of the vertex is x = -b/2a.  Find that and plug it into the equation to find the y coordinate of the vertex.

anonymous · Answer

So, h= $$-b/2a$$
which equals $$-4/2(x^2/2)$$

then I plug h into the original equation to find k

anonymous · Answer

The thing I'm struggling with is the... complex fraction? I think that's what it's called. a fraction underneath a fraction. How do I deal with that?

mertsj · Answer

|dw:1325197684345:dw|