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Mathematics 13 Online
OpenStudy (anonymous):

What's inverse and direct variation?

OpenStudy (jamesj):

For example, force varies directly with mass; F = ma And acceleration varies inversely with m, a = F/m Formally, a variable or quantity y varies DIRECTLY with another variable/quantity x, if there is a constant k such that y = kx y varies INVERSELY with x if there is a constant k such that y = k/x

OpenStudy (anonymous):

Wow, you're really good at explaining. :) See I'm having trouble with this little chart...

OpenStudy (anonymous):

OpenStudy (jamesj):

So suppose y is a function of h. Does it vary directly or inversely? If it varies directly, then there exists a constant k so that y = kh Does there exist such a constant?

OpenStudy (mertsj):

If you multiply x times y and always get the same number that is inverse variation.

OpenStudy (jamesj):

(that's an equivalent statement, yes.) But coming back to your problem ... is there a constant k such that y = kh ?

OpenStudy (jamesj):

If there is such a number k, then y/h = k.

OpenStudy (mertsj):

If you divide y by x and always get the same number that's direct variation.

OpenStudy (mertsj):

So which is the table you posted? Direct or Inverse?

OpenStudy (anonymous):

JamesJ Direct variation right?

OpenStudy (anonymous):

Oh sorry mertsj yeah i think its direct

OpenStudy (jamesj):

Yes, and what is the constant k such that y = kh?

OpenStudy (anonymous):

10?

OpenStudy (jamesj):

yes, clearly.

OpenStudy (anonymous):

Lol yes..

OpenStudy (anonymous):

So the variables h and y show direct variation?

OpenStudy (jamesj):

Yes, because there is a number k, a constant, such that y = kh

OpenStudy (jamesj):

(Technically we want k to be not zero, and here it is 10, which isn't zero so we're in the clear. Can you see why we wouldn't want k = 0?)

OpenStudy (anonymous):

5 * 0 = 0 4 * 0 = 0 2 * 0 = 0 where is the variation?

OpenStudy (anonymous):

Not so much....

OpenStudy (anonymous):

Why does it need to be 0?

OpenStudy (anonymous):

*not 0

OpenStudy (jamesj):

In both cases, we're trying to describe how the variable x changes or impacts the variable y. If y is directly proportional to x, then as x increases in magnitude, y increases in magnitude. You can see that with your example of y and h. As h increases, y increases; as h decreases, y decreases. If y is inversely proportional to x, then the opposite occurs: - as x increases, y decreases - as x decreases, x increases If you have y = kx and k = 0, then we have y = 0x = 0. So y doesn't change _at all_ as x changes. That defeats the purposes of describing how one variable changes with another. In this case with k = 0, y does not change as x changes. So it's not useful to describe x and y to as being directional proportional.

OpenStudy (anonymous):

So x and y can't be described as being directional proportional.

OpenStudy (jamesj):

if changes in x result in no change in y (or vice versa), no. We do not say in that case that the two variables are directly proportional. (And I should have written in my last sentence above directly proportional, not 'directional')

OpenStudy (anonymous):

Alright! (Haha! I was gonna say...)

OpenStudy (anonymous):

Thanks SO much... I'm a lost cause when it comes to math! :)

OpenStudy (jamesj):

don't say that. it takes work, like everything smart. But the payoff is huge.

OpenStudy (jamesj):

;-)

OpenStudy (anonymous):

Sometimes...! ;) And on top of that i probably have a teacher who knows less then i do... not even joking... So that only helps me being a lost cause! :P

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