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Mathematics 15 Online
OpenStudy (anonymous):

can u find the sum of these numbers?

OpenStudy (anonymous):

OpenStudy (mr.math):

I can.

OpenStudy (mr.math):

You want to try first?

OpenStudy (turingtest):

here's the idea: if we can make the two terms have the same number under the radical, then we can combine like terms so try to get the second term be "something times radical 6" and see what you get.

OpenStudy (anonymous):

2\[2\sqrt{6} \] is 12

OpenStudy (anonymous):

HINT: \( \sqrt{24} = \sqrt{2 \times 2 \times 2 \times 3 } = 2 \sqrt{6} \) can you do the rest ?

OpenStudy (anonymous):

so it would be

OpenStudy (turingtest):

No... how did you get \[4\sqrt3\]? FFM showed you how to get both radicals to have a 6 under them. use that.

OpenStudy (anonymous):

\[4\sqrt{3}\] u get 2*2+3+2=9

OpenStudy (anonymous):

OH! its

OpenStudy (turingtest):

Yes it is =)

OpenStudy (anonymous):

:)

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