An object will take t sec to drop d feet, where t = $$\sqrt{d/16}$$. what distance will it drop in $$\sqrt{19}/2$$ sec?
I got 19ft.

Question

anonymous · Answer

i think it might be 38 though

lollylau · Answer

76?

paxpolaris · Answer

$$t= \sqrt{d/16}={\sqrt{d}\over4}$$

lollylau · Answer

sqrt(19)/2=sqrt(d/16)
19/4=d/16
d=76?

paxpolaris · Answer

$${\sqrt{19}\over2}={\sqrt{d}\over4}$$$$\sqrt d = 2 \sqrt{19}$$
$$\huge \therefore d=76$$

anonymous · Answer

But the question isn't asking the value of d

paxpolaris · Answer

yes it is ... 76 ft

lollylau · Answer

d = distance
distance = unknown
unknown = answer
therefore, d = answer

anonymous · Answer

Yes, answer is 76 feet

anonymous · Answer

either way i got it wrong thanks for all your help. i got 2 more i want to check but im too tired to type. gonna play a video game, hehe.