Answer 1

um.?

Answer 2

no way, not real.
difficult to read too.

Answer 3

https://docs.google.com/present/edit?id=ddd7shbj_1hnwt4pcg

Answer 4

No way.

Answer 5

probe this please

Answer 6

1. substitution
- let p and k , two prime numbers greater or equal 2,from the set of prime numbers, P,
in the form : p=2a + 1 and k=2b + 1 , such that a and b are natural numbers,from the set of natural numbers N,
- let m=2n ,m greater or equal 4,even number,from the set of natural numbers N and n grater or equal 2,natural number from set of natural numbers N,
2. conclusion
- every even integer greater than 2 can be expressed as the sum of two primes
3. demonstration
* - step 0. for n=2 --- m=4 --- 4=2+2
** - step 1. for - if n is greater or equal 3 so always will be a number a and b such that n=a + b + 1
- dem. 3=1+1+1 4=2+1+1
5=2 +2+1 ................ n=a+b+ 1
- so for n=k than k=a+b+1 - suppose that is true
- for k+1=(a+b+1)+1=(k)+1=k+1
- so for k+1 is true
- for n grater than 2 always will be a number a and b such that n =a+b+ 1
*** - step 2.
- every even integer greater than 4 can be expressed as the sum of two primes
m=p+k
- demonstration by ,,reductio ad absurdum"
- so than m is not equal p+k
- so than 2n is not equal 2a+1+2b+1
- so than 2n is not equal 2a+2b+2 / divide both sides by 2
- so than n is not equal a+b+1 - so but n=a+b+1 was proved that is true
- so than m=p+k is proved that is true

Answer 7

Is this your proof?

Answer 8

these are there - on this website too

Answer 9

somebody cannot spell, but I have serious doubt about things like the induction part and the reduction ad absurdam.

Answer 10

Its very hard to read =/ You shouldn't need demonstrations in a formal proof. The fact that you have demonstrations means you think you had to clarify some points, but instead of demonstrations, you should revise the point you are trying to make.

Answer 11

hello all and happy new year!

Answer 12

happy new years !

Answer 13

Happy new year, though it appears Goldbach's Conjecture remains unproven =(

Answer 14

new start partying and forget about math until 2012

Answer 15

lol, im down for that.

Answer 16

make it until 2020

Answer 17

You say
so than m is not equal p+k
- so than 2n is not equal 2a+1+2b+1

but there are numbers of the form c= 2a+1 and d=2b+1 that are not prime. For example, let a= 4, b= 7, so c= 9, d= 15
2*12 = c + d = 2*a+1 +2*b+1
You cannot conclude 2n is not equal 2a+1+2b+1