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[9.02] What are the solutions of 6x2 − x − 2 = 0?
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fined the like turms
1t step : \[6x ^{2} + 3x - 4x - 2 = 0\]
2nd : \[3x(2x+1) - 2(2x+1) = 0\]
do you get it so far?
then the 3rd step would be : (3x-2)(2x+1) = 0
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therefore the solution should be x = \[2\over3\] and \[-1\over2\]
I hope I am right :) :) happy new years :p
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