Question

"Find x > 3 such that

ln(x) < x^(0.1)"
Answer me Please i need it for the test !

Answer 1

Help!

Answer 2

A take home test? ....

Are we allowed to graph?

Answer 3

If this is a take home test then it might not be good to answer it.

Answer 4

please help me man :(

Answer 5

HAAAAAAAAAAAAALPPPPPPPPPP!!!

Answer 6

3.01

Answer 7

oh i see it is wrong. have to go further out!

Answer 8

Help me guys

Answer 9

what vishal says. 3.01 works

Answer 10

http://www.wolframalpha.com/input/?i=ln%283.01%29%2C3.01^.1

Answer 11

i was wrong earlier, 3.1 does not work

Answer 12

thanks...

Answer 13

nono i think i have the answer i think it is X = 3.0597 or not?

Answer 14

?? the question says
"Find x > 3 such that ln(x) < x^(0.1)"
there are infinite such x's

Answer 15

did you see my question? Are we allowed to graph? Do you have a graphing calculator?

Answer 16

i found it !!! the answer is
x>11ln0.1/1-(0.1)^11

Answer 17

if you are trying to solve
\[\ln(x)=x^{.1}\] you will get something like
\[x=3.05973\] but i have no idea how you are going to solve it

Answer 18

oh my god.... i will going to be worse in that exammmmmmmmmmmmmmmm

Answer 19

if the question says "find x" then what is wrong with 3.01? maybe i don't understand the question.
if it is "solve
\[\ln(x)=x^{.1}\] that is quite a different problem

Answer 20

which is not trivial by any means, and if you are expected to answer with a decimal then i guess you need to use a graphing calculator. here is what i got with wolfram
http://www.wolframalpha.com/input/?i=ln%28x%29%3Dx^.1
click on "exact form" to view the decimal