Write the equation of the line that is parallel to the line 3x − y = −3 and passes through the point (4, −2). ?? how do u do this?
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OpenStudy (karatechopper):
well what is your slope?
OpenStudy (anonymous):
Karate!!
OpenStudy (karatechopper):
GT!!
OpenStudy (karatechopper):
anyways jazlin what is your slope?
OpenStudy (anonymous):
hpw would i find the slope?
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OpenStudy (anonymous):
To find slope, you need to re-arrange the equation into y=mx+b form where m is the slope.
OpenStudy (anonymous):
i did that but i dont know how to completely slove it like this is what i put -2=m(4)+6
OpenStudy (anonymous):
sorry i ment +b
OpenStudy (anonymous):
3x-y=-3
=> y = 3x+3
So, slope = 3.
OpenStudy (anonymous):
Now, you need to find the equation of the line parallel to this line and passing through point (4,-2).
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OpenStudy (anonymous):
Parallel lines have same slope. So, the new line must have a slope of 3. So, it must have the equation:
y = 3x + b. To find b, you should use the fact that this line passes through point (4,-2).
OpenStudy (anonymous):
so the it would be -2=3(4)+b nd i have to solve it ?
OpenStudy (anonymous):
does b=-6?
OpenStudy (anonymous):
You got part of it.
-2 = 3*4+b
=> -2 - 12 = b = -14
So, new line is:
y = 3x-14