Question

A new problem #6

Answer 1

given,
\[x ^{1}+x _{2}+x _{3}+...+x _{1998}+x _{1999}=1^{3}\]
\[x _{2}+x _{3}+...+x _{1998}+x _{1999}=2^{3}/3\]
\[x _{3}+...+x _{1998}+x _{1999}=3^{3}/5\]
.
.
.
\[x _{1998}+x _{1999}=1998^{3}/3995\]
\[x _{1999}=1999^{3}/3997\]

find
\[\sqrt{1^{2}x _{1}+2^{2}x _{2}+3^{2}x_{3}+...+1998^{2}x _{1998}+1999^{2}x _{1999}}=?\]

\[a.1,999,900\] \[b.1,999,090\] \[c.1,999,000\] \[d.1,909,990\]

P.S. as ever, if you cannot do it within 10 minutes, give me your medal LOL

Answer 2

i made a little mistake
the second line \[x _{1}+x _{2}+.....=1^{3}\]

Answer 3

on the way

Answer 4

do you guys want a hint?

Answer 5

no

Answer 6

ok fine

Answer 7

my answer isnt matching to any of the option(calculation mistake maybe) but i tryed
\[\sqrt{3988012994002}\]

Answer 8

good work binary3i

Answer 9

for the solution.
1.make RHS to be an integer by multiply what's divide under them to LHS for each equation
2.sum it up
and look for what you want

Answer 10

I think the answer is c