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Mathematics 14 Online
OpenStudy (anonymous):

Factor out the greatest common factor from the expression 14yz^3 + 28xy^2z – 7y^2z^2

OpenStudy (anonymous):

Well, we gotta begin by finding something in common with all the terms

OpenStudy (anonymous):

Would it be possible if you stay and help me with several of these please?

OpenStudy (anonymous):

Right of the bat i see we can factor out a 7 a "y" and a "z", so it would be 7yz

OpenStudy (anonymous):

something in common would be 2

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

true but its not the highet possble factor, you see what we do is we look at each term adn see what is the highest possible factor each term has in common

OpenStudy (anonymous):

7yz(2z2 + 4xy – yz) right

OpenStudy (anonymous):

you got it

OpenStudy (anonymous):

okay cool

OpenStudy (anonymous):

Factor out the greatest common factor from the expression 16x^3y^2z^3 – 2x^2yz^3 + 14y^3z^4

OpenStudy (anonymous):

the GFC would be 2 right

OpenStudy (anonymous):

autamatically , i see that 2 would be something we can factor out

OpenStudy (anonymous):

so it would be 2yz right?

OpenStudy (anonymous):

well, you got two of the three right, 2y for sure, but if you notice all the terms have z^3 in common, so it would be 2yz^3

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

2yz^3(8x^2y^4z+7x^2y^3)

OpenStudy (anonymous):

I see where I went wrong

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

2yx^2(8x^3y - x^2 + 7y^2z) is my answer right

OpenStudy (anonymous):

I forgot to subtract the x^2

OpenStudy (anonymous):

the answer would be 2yz^3(8x^3y-x^2+7y^2z)

OpenStudy (anonymous):

so you got it

OpenStudy (anonymous):

awesome thank you for double checking my work

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