a cash box contained 14.55 in quarters,D,N. if there were 3 more than twice as many D as N and three less than three times as many Q as N how many of each does she have?
help
D=number of dimes N=number of nickels Q=number of quarters N=3+2D N=3Q-3 5N+25Q+10D=1455 Have I got this right? !!!!
If so there is three equations with 3 unknowns and can be solved.
Somewhere I erred in the translation. If there were 3 more than twice as many dimes as nickels. What is that saying? N=2D + 3 ??? Someone help ISA DIA
With the relationships I had in my first post, I come out with a fraction for the number of nickels.....I know that can't be correct. Are you there robtobey??
A Mathematica solution is attached.
Thanks robtobey, hopefully ISA DIA is still interested.
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