Question

systems of equations
y=4 third x plus 3
y= negative x minus 4

Answer 1

so
y=4/3x+3
y=-x-4
soooo, let's find the x!
in the second equation for example: x=-y-4 ok? Sostitute this x in the first equation
=> y=4/3*(-y-4)+3 resolve => y=-4/3y-16/3+3 => 3/3y+4/3y=-16/3+9/3
sooo: 7/3y=-5 => y=-15/7 tadaaaaa you find y! now sostitute this y to the second equation: -15/7=-x-4 => x=-28/7+15/7 => x=-13/7 !!! finish ;)

Answer 2

i don't follow

Answer 3

i don't see why you swapped out the -x for -y

Answer 4

?i don't undertand, sorry, but I'm not english XD

Answer 5

and thats not even the right answer

Answer 6

x = -3

Answer 7

probably I do wrong calculus, but the main idea is this

Answer 8

i have the answers just want to know how to do the problem

Answer 9

and its not even calculus its algebra 1

Answer 10

i intend calculate for caluclus XD

Answer 11

so, if you're ready we try to make another time this sistem