i need to show my work like that lets try the other examples :D
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OpenStudy (akshay_budhkar):
so now we know \[\sqrt{4}=2\]
OpenStudy (pokemon23):
yes :D
OpenStudy (akshay_budhkar):
ok sure. so we have \[\sqrt{20}=2\times \sqrt{5}\]
OpenStudy (akshay_budhkar):
so the main concept is you prime factorize the number inside the square root
OpenStudy (pokemon23):
\[\sqrt{20}=2\times \sqrt{5} \] so this is the correct answer but why does 5 have a square root sign?
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OpenStudy (akshay_budhkar):
then if you have some thing like \[\sqrt{x}\times \sqrt{x}\] you know it is x
OpenStudy (akshay_budhkar):
because you just have \[\sqrt{5}\] you can't simplify it further can you?? for 2 you had \[\sqrt{2}\times \sqrt{2}\] which turned out to be 2
OpenStudy (akshay_budhkar):
So you getting it?
OpenStudy (pokemon23):
\[\sqrt{20}=2\times \sqrt{5}\] but how is it 20?
OpenStudy (akshay_budhkar):
\[(\sqrt{5})^2=\sqrt{5\times} \sqrt{5}=5\]
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OpenStudy (akshay_budhkar):
ok we can write 2 as \[\sqrt{2}\times \sqrt{2}\]
so we have \[2\times \sqrt{5}=\sqrt{2\times} \sqrt{2}\times \sqrt{5}=\sqrt{2\times2\times5}=\sqrt{20}\]
OpenStudy (pokemon23):
so simplest form is \[2\times \sqrt{5}\]
OpenStudy (akshay_budhkar):
yes right
OpenStudy (akshay_budhkar):
so u getting the glimpse of how to solve such problems?
OpenStudy (pokemon23):
i guess
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