01.03 MA.912.A.3.1

Solve –3(2x – 1) = x + 10. You must show all work.

Question

01.03 MA.912.A.3.1

Solve –3(2x – 1) = x + 10. You must show all work.

anonymous · Answer

i think it's 
–3(2x – 1) = x + 10
      -3               -3   
(2x - 1) = (x + 10)/3
    -x              -x         
x - 1 = 10/3
  +1       +1  
  x   =  3 1/3 ( This is 3 and one thirds )

anonymous · Answer

but it's not right, i think

anonymous · Answer

Distribute the -3 to the (2x-1)
= -6x+3

anonymous · Answer

–3(2x – 1) = x + 10-- distribute
-6x+3=x+10--- now combine like terms
adding 6x to both sides so the 6 in the left is cancel out and ur left with 3=7x+10-- now subtract 10 to both sides so the 10 in the right equals 0 and its cancel out... ur left with -7=7x--- divide by 7 so -1=x!!!

anonymous · Answer

Yea, what she said lol

anonymous · Answer

did it help or you still don't understand?

anonymous · Answer

$$-3(2x-1)=x+10$$
$$-6x+3=x+10$$
$$3=7x+10$$
$$-7=7x$$
$$\frac{-7}{7}=x$$
$$-1=x$$

anonymous · Answer

i'm good