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Mathematics 9 Online
OpenStudy (anonymous):

factor 2x^2-2x+4

myininaya (myininaya):

each term has 2 in common

myininaya (myininaya):

so you can factor 2 out

myininaya (myininaya):

\[2(x^2-x+2)\]

myininaya (myininaya):

now you should look at factoring x^2-x+2

myininaya (myininaya):

Is this factorable?

myininaya (myininaya):

There are no factors of 2 that have product 2 and sum -1. So we are done.

OpenStudy (anonymous):

mmm i dont think it is factorable

OpenStudy (anonymous):

i think it should be 2(x-x1)(x-x2)

OpenStudy (anonymous):

x1 and x2 being exponents?

myininaya (myininaya):

You just want to factor this over the integers right? If so what I gave is right.

OpenStudy (anonymous):

2(x^2-x+2)

OpenStudy (anonymous):

no, solve the equation x^2-x+2=0, x1,x2 are roots

OpenStudy (anonymous):

well this is not the original problem i just got stuck in this part but i might done something wrong on the way... the original problem is

OpenStudy (anonymous):

|dw:1325742314079:dw| and im supose to simplify that

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