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factor 2x^2-2x+4
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each term has 2 in common
so you can factor 2 out
\[2(x^2-x+2)\]
now you should look at factoring x^2-x+2
Is this factorable?
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There are no factors of 2 that have product 2 and sum -1. So we are done.
mmm i dont think it is factorable
i think it should be 2(x-x1)(x-x2)
x1 and x2 being exponents?
You just want to factor this over the integers right? If so what I gave is right.
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2(x^2-x+2)
no, solve the equation x^2-x+2=0, x1,x2 are roots
well this is not the original problem i just got stuck in this part but i might done something wrong on the way... the original problem is
|dw:1325742314079:dw| and im supose to simplify that
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