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Mathematics 8 Online
OpenStudy (anonymous):

what is the answer if you factor out 25x^4+16x^2 y^2+4Y^4

OpenStudy (anonymous):

Is that \[25x^4+16x^2y^2+4y^4\]?

OpenStudy (anonymous):

its 16x to the power of two then y to the power of 2

OpenStudy (anonymous):

\[ \left(5 x^2-2 x y+2 y^2\right) \left(5 x^2+2 x y+2 y^2\right) \]

OpenStudy (anonymous):

\[(5 x^2 - 2 x y + 2 y^2) (5 x^2 + 2 x y + 2 y^2)\]

OpenStudy (anonymous):

may i ask how did you derive from thet answer?

OpenStudy (anonymous):

If you let \[a=x^2\] and\[b=y^2\] then you would have: \[25a^2+16ab+4b^2\] Take a good look at the constants, they are actually very much factorable.

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

Sure, no problem.

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