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Mathematics 12 Online
OpenStudy (anonymous):

I need help Graph the following inequalities: -3x – 1 < -7

OpenStudy (amistre64):

one variable means we get a line as a graph

OpenStudy (amistre64):

when does -3x-1 = -7?

OpenStudy (anonymous):

see I do not understand this I have been trying to understaND it but cant :(

OpenStudy (amistre64):

how much do you understand ? so i have something to work off of

OpenStudy (amistre64):

do you know what a variable represents? what an equation is meant to communicate? how to find missing values?

OpenStudy (anonymous):

no not really see I went to home school and I didnt learn all this when I was in home school and now I am in college and can not figure out how to do this I feel so dumb

OpenStudy (amistre64):

the math itself is pretty simple; its the notation thats a bit strange to people. you already know how to add subtract multiply and divide ... right? if so, then this is just a matter of knowing what the equation is telling us to do

OpenStudy (anonymous):

yes I know how to add and subtract and mult and divid

OpenStudy (amistre64):

and equation is a balancing act. the left side of the "=" is equal in value to the right side so what we need to know is that whatever we do to one side HAS to be do to the other to keep the thing balanced.

OpenStudy (amistre64):

lets work thru this then: -3x -1 = -7 if we get the "x" all alone on one side, and have a value on the other side, then we know what the "x" is equal to

OpenStudy (amistre64):

we start by getting rid of any addition or subtraction that is in our way; so lets add off that (-1) to both sides to start with: -3x -1 = -7 +1 +1 ------------ -3x + 0 = -6 -3x = -6

OpenStudy (amistre64):

does that make sense so far?

OpenStudy (anonymous):

yeah kind of

OpenStudy (amistre64):

explain it to me in your own words, teach me what I just taught you

OpenStudy (anonymous):

you should try to make both side even like is you have a - number on one side and + number on the other side you want to try to take the - away and make it a even ? am I right

OpenStudy (anonymous):

so far?

OpenStudy (amistre64):

sounds good so far :)

OpenStudy (anonymous):

ok cool

OpenStudy (amistre64):

so, what we are left with since we took care of that (-1) and there is not more adding or subtracting to deal with is: -3x = -6 that -3 is stuck on our "x", its "m"arried to it, and we need to "d"ivorce the -3. or in math talk. that -3 is "multiplied" to our x and need to be "divided" off. and what we do to one side we do to the other. -3x = -6 \-3 \-3 --------- 1x = 2 so, x = 2

OpenStudy (amistre64):

if that makes sense, then we are about halfway done, we still need to determine a graph for this :)

OpenStudy (anonymous):

yeah it is makeing more sence thank you for helping me out this is making more sence than the help other people has tried

OpenStudy (amistre64):

your welcome, after about a couple hundred of these things you get a knack for it thats almost intuitive :)

OpenStudy (amistre64):

to graph this thing we need to draw a line <--------------------------------> we know that: -3x-1 = -7, when x=2. so lets put a "2" on our line. <--------------------------------> 2 this is the foundation for the real question. We dont want to know when -3x-1 is EQUAL TO -7; but when it is LESS THAN -7 we have to determine which side of this "2" fits. since 0 is a nice round number we can test that side to see if it works.

OpenStudy (amistre64):

<--------------------------------> 0? 2 -3(0) -1 < -7 0 - 1 < -7 -1 < -7; this is a false statement so we need to pick the OTHER side of our "2". <--------------------------------> 0 (2)----------------> this tells us that every thing bigger than "2" is a solution.

OpenStudy (anonymous):

cool that make sence

OpenStudy (amistre64):

yay!! :) hope it helps

OpenStudy (anonymous):

yes it did thank you so so much !!!!!

OpenStudy (amistre64):

youre welcome, and good luck ;)

OpenStudy (anonymous):

do you think you can help me out one more time with this other problem please ?

OpenStudy (amistre64):

sure, now that the basics have been addressed it should go quicker

OpenStudy (amistre64):

go ahead and type it up on the left and we can work thru it

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