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Mathematics 21 Online
OpenStudy (anonymous):

TT or across, teach me some algebra!!!

OpenStudy (anonymous):

who is TT ?

OpenStudy (anonymous):

TuringTest

OpenStudy (anikate):

what is x in this equation? 6+x=2

OpenStudy (anonymous):

-4

OpenStudy (anikate):

good job that was basic

OpenStudy (anonymous):

I have been studying basic algebra.

OpenStudy (anikate):

x^2*x^3

OpenStudy (anonymous):

x^5

OpenStudy (anonymous):

x+y=6 x-y=7 can you find the x and y?

OpenStudy (anikate):

(x^3)^2

OpenStudy (anikate):

x=7+y

OpenStudy (anonymous):

Anikate, he meant me.

OpenStudy (anonymous):

FFM give me another one

OpenStudy (anikate):

oh ok...

OpenStudy (anonymous):

\( a+b=9 \) \( a-b=11 \) what is \( a \) and what is \(b\) ?

OpenStudy (anonymous):

a=10 b=-1 or a=9-b b=9-a

OpenStudy (anonymous):

Okay .. do you understand the difference between variable and constant?

OpenStudy (anonymous):

variable is something you put instead of a number, right?

OpenStudy (anonymous):

More importantly, do you understand what in earth an equation means?

OpenStudy (anonymous):

Excuse me?

OpenStudy (anonymous):

Precisely, variable is something that varies, so yes you are right :)

OpenStudy (anonymous):

Were you just calling me stupid?

OpenStudy (anonymous):

No,lol :D you misunderstand my tone :) So what is an equation ?

OpenStudy (anonymous):

Its a line that states values of variables, i guess

OpenStudy (anonymous):

Hm. Let me explain.

OpenStudy (anonymous):

A equation has two parts, right hand side and left hand side.

OpenStudy (anonymous):

I know that

OpenStudy (anonymous):

Anything right of the '=' sign is right hand side

OpenStudy (anonymous):

I know, if you do something to the LHS you have to do the same to the RHS

OpenStudy (anonymous):

yadda yadda, i know all that.

OpenStudy (anonymous):

Good :D

OpenStudy (anonymous):

Hey, that's not the right attitude towards mathematics :)

OpenStudy (anonymous):

anyways back to the problem our hand: a+b=9 a−b=11

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

we want to find a and b in terms of constants only.

OpenStudy (anonymous):

So whats a constant?

OpenStudy (anonymous):

How could we do that ?

OpenStudy (anonymous):

constant is something which value is fixed.

OpenStudy (anonymous):

Ok, so we can subtract a from both sides to get b on the top one, right?

OpenStudy (anonymous):

Why don't we add the equations? like this \[ a+b+a-b=9+11\]

OpenStudy (anonymous):

Oh you want me to use both equations?

OpenStudy (anonymous):

Well we can simplify that to a2=20, right?

OpenStudy (anonymous):

Cause the b's cancel eachother out

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

And for a we can just divide both sides by 2 getting x=10

OpenStudy (anonymous):

a=10*

OpenStudy (anonymous):

Good, now what about b ?

OpenStudy (anonymous):

a+b+a−b=9+11 a2 +b=20+b Am i doing alright so far?

OpenStudy (anonymous):

no, you need to subtract this time

OpenStudy (anonymous):

Subtract what exactly?

OpenStudy (anonymous):

a+b-a+b=9-11

OpenStudy (anonymous):

Is is (a+b)-(a+b) or without parenthesis?

OpenStudy (anonymous):

second equation from the first.

OpenStudy (anonymous):

Oh i see, this si the second one?

OpenStudy (anonymous):

(a+b)-(a-b) without parentheses

OpenStudy (anonymous):

a+b-a+b=9-11 2b=9-11 2b=-2 b=-1

OpenStudy (anonymous):

See? I can do this!

OpenStudy (anonymous):

Very good :)

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

Gimme something harder!

OpenStudy (anonymous):

If ax - a = x - 1 what is x equal to?

OpenStudy (anonymous):

Divide both sides by x, right so far?

OpenStudy (anonymous):

No wait, ax - a = x - 1 ax=x-1+a x=x-1 Im stumped

OpenStudy (anonymous):

First, bring all the x terms to one side, and everything else to the other.

OpenStudy (anonymous):

Im sorry, i havent studied factoring yet :/

OpenStudy (anonymous):

Ok. Here's the solution ax - a = x - 1 ax - x - a = -1 ax - x = a - 1 x(a - 1) = a - 1 hence x = 1

OpenStudy (anonymous):

Ok, youll have to give me another one tommorrow so i can try :D

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