3. Segment AB is the diameter of circle M. The coordinates of A are (−4,3).
The coordinates of M are (1,5). What are the coordinates of B?

(1) (6,7) (3) (−3,8)

(2) (5,8) (4) (−5,2)
how do i show work???

Question

3. Segment AB is the diameter of circle M. The coordinates of A are (−4,3).
The coordinates of M are (1,5). What are the coordinates of B?

(1) (6,7) 			(3) (−3,8)

(2) (5,8) 			(4) (−5,2)
how do i show work???

kainui · Answer

First off, draw a picture and label the points and label B as (x,y) and solve with the pythagorean theorem since the distance between two points is the hypotenuse of a right triangle!

anonymous · Answer

$$(x-a)^2 + (y-b)^2 = r^2$$where M(a,b) is the center of the circle. 
We know that$$r = \sqrt{(x_A -x_M)^2 - (y_A - y_M)^2}$$Point B must lie on the circle and the line through Point A and Point M. The equation of the line through $\bar{AB}$ is $$y - y_A = m(x-x_A)$$where $m = {y_A - y_M \over x_A - x_M}$
We have two equations and two unknowns. We can solve one for an expression for x, plug that expression for x into the other, come up with a number for y, plug y back into the expression for x to get a value for x.