Question

6x^2 + x = 2 . How ?

Answer 1

Know the quadratic formula?

Answer 2

Don't Remember How Its Goes ; Like The Order Of It .

Answer 3

\[\Large \begin{array}{l}
6{x^2} + x = 2\\
6{x^2} + x - 2 = 0
\end{array}\]
Use the quadratic formula:\[\Large \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]To find the roots.

Answer 4

^

just rearrange the eq. to make it equal to 0.
a = x^2 term
b = x term
c = number term

And then you'll come out with two answers for x

Answer 5

you can also factorize:
(3x+2)(2x-1)=0
then solve...

Answer 6

Factoring works on this one, but not on all of them ...

Answer 7

Yeah it's definitely worth knowing how to factorise, but not everything has nice integer factors.
\[\Large \begin{array}{l}
\frac{{ - 1 \pm \sqrt {{1^2} - (4 \cdot 6 \cdot - 2)} }}{{2 \cdot 6}}\\
= \frac{{ - 1 \pm \sqrt {49} }}{{12}}\\
= \frac{{ - 1 \pm 7}}{{12}}\\
= \frac{1}{2}, - \frac{2}{3}
\end{array}\]