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Mathematics 16 Online
OpenStudy (anonymous):

find the number of ways to arrange the letters in SYLLABLES.

OpenStudy (mattfeury):

There is a formula for this. Are you familiar with combinatorics or permutations?

OpenStudy (anonymous):

NOPE i hate these!!

OpenStudy (anonymous):

9!

OpenStudy (anonymous):

NOO

OpenStudy (mattfeury):

I believe the formula is this: n number of letters total and z number of "repeats," where \(k_z\) is the number per letter \[\frac{n!}{k_1!k_2!...k_z!}\]

OpenStudy (anonymous):

9!/(3!2!)

OpenStudy (anonymous):

YESS thats it i dont know how to solve i though

OpenStudy (anonymous):

hmmm.....yeah the 3 Ls.

OpenStudy (mattfeury):

how many letters are in "SYLLABLES" ? 9 so n = 9 let's each letter: "S" - there are 2 "s"s "Y" - only 1 y "L" - there are 3 "L"s "A" - only 1 "B" - only 1 "E"- only 1

OpenStudy (anonymous):

\[\Large \frac{{9!}}{{3! \cdot 2!}} = \frac{{362880}}{{12}} = 30240\]

OpenStudy (mattfeury):

these are your k values. so you get this: \[\frac{9!}{2! * 1! * 3! * 1! * 1! * 1!}\] of course, 1! = 1

OpenStudy (mattfeury):

does that make sense?

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