(p ↔ q) → p - how to construct a truth table? pls help; so confused!
do it in steps starting with just p and q. p can only be True or False, same with q p<->q is biconditional which means p will be same as q and vice versa Let m = p<->q m -> p means m implies p so if m is true, then p is true Now put it together in a table p q p<->q m->p ----------------------- F F T F F T F F T F F F T T T T
OMG thank you so much. I have been working on this one problem for literally hours!! I truly apreciate your help!
F->T is true F->F is true
hmm i may have messed up thanks zarkon yeah the only time an implication is F is if you have T->F
Zarkon, thanks for your respose as well. Is this the same answer as the original response by dumbcow but written a different way?
LOL OKay, don't confused me... so, I can write the answer exactly like you have it Zarkon?
yeah just change the last column to F T T T
Thank y'all so much!!!!
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