Question

Divide using polynomial long division

(x^3-3x^2+4x-6)/(x^2-4)

Answer 1

i did this but came up with x-4 remainder 12x+10 and im not sure that could be an answer

Answer 2

Check these out:

http://en.wikipedia.org/wiki/Polynomial_long_division
http://www.purplemath.com/modules/polydiv2.htm

Answer 3

x
___________________
x^2-4 | x^3-3x^2+4x-6


x
___________________
x^2-4 | x^3-3x^2+4x-6
- (x^3 -4x)
-------------------------
0 -3x^2+8x-6
-3x^2+8x-6

x-3
___________________
x^2-4 | x^3-3x^2+4x-6
- (x^3 -4x)
-------------------------
0 -3x^2+8x-6
-3x^2+8x-6


x-3
___________________
x^2-4 | x^3-3x^2+4x-6
- (x^3 -4x)
-------------------------
0 -3x^2+8x-6
-3x^2+8x-6
-{-3x^2+12)
--------------------------
0+8x-18
8x-18

So the answer is that x^2-4 divides into x^3-3x^2+4x-6, x-3 times with a remainder of (8x+6)/(x^2-4)