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Mathematics 10 Online
OpenStudy (anonymous):

if a person had a calling card worth $20.Long distance calls cost $0.05 more per minute than local calls. the person made 35 min. of local calls and 52min. long-distance calls, what was she paying per minute for each type of call?

OpenStudy (anonymous):

If this assumes that the entire card was used, then you're solving for 20 = 35L + 52 D where L is the price for local and D is the price for long-distance. Since long-distance is set for 5 cents more per minute, D = L + 0.05. Knowing that, plug in L + 0.05 for D in the original equation and solve for L. Then, using the numerical value of L, solve for D.

OpenStudy (anonymous):

I don't understand what you are saying

OpenStudy (anonymous):

If 20 dollars was used, then you can calculate the price of minutes based on it. 35 minutes times the price of local minutes + 52 minutes times the price of long-distance minutes = 20 dollars

OpenStudy (anonymous):

Since long distance minutes are the same as local minutes but 5 cents more, you could rewrite it as: 35 minutes times the price of local minutes + 52 minutes times the price of local minutes + 52 times 0.05 = 20 dollars or 35L + 52(L+0.05) = 20

OpenStudy (anonymous):

thank you

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