For which values of the constant "k" does the system: x - y = 3 2x - 2y = k have no solutions? exactly one solution? many solutions? explain your reasoning.
so you want parellel lines this means you want the same slope but different y-intercept
i'm talking about for the no solution part of the question
this is a system of linear equations question like matrixes and stuff
but both in this form y=mx+b
\[y=x-3\] \[y=x-\frac{k}{2}\]
yes k = 6
so for no solution we need k/2=3
great! thats for the first part of the question
but you have to explain for which values of k results in no solutions, one solution and many solutions
yes we did the first part
now we are looking for exactly one solution which is impossible
so what is it no solutions, one solution or many solutions
these lines can either have infinitely many solutions are no solution
there is no value of k that will give us one intersection
oops i did the infinitely many part first
for infinitely many solutions k=6
for no solutions you want the y-intercepts to be different since the slopes are already the same
so for no solution k can be anything but 6
so how would i explain that there cannot be one solution?
because theses lines have the same slope
you can therefore only have infinitely many or no solution
infinitely many=same slope and same y-intercept no solution= same slope and different y-intercept
one solution=different slope and a whatever y-intercept( same or different)
it is impossible here for that 3rd case i mentioned
I UNDERSTAND THANK YOU SOO MUCH :)
np :)
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