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how do you put into formula 3 times a number + 2 times the second number = 4 times the third number and the have to be integers in a row. I found 14, 15, 16 but how do you show the formula
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and the total of the first two are 8 less than the thrid
8 more sorry
put the first number at x, second is x + 1, third is x+2 then \[3x+2(x+1)=4(x+2)\]
oh wait, total of first two are 8 less than the third would be \[x+x+8=x+2\]
Let me say it again 3 times the first integer plus two times the second integer is more than 8 four times the third integer
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3 times the first plus 2 times the second is 8 more than 4 times the third?
if so then\[3x+2(x+1)=4(x+2)+8\]is the formula
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