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Mathematics 15 Online
OpenStudy (anonymous):

what set of coefficients would balance the equation Mg+AlCl3---->Al+MgCl3

OpenStudy (jamesj):

You'll have more luck with this question in Chemistry. But if you're here I'll help you.

OpenStudy (jamesj):

What's the basic rule we use to balance chemical equations?

OpenStudy (jamesj):

talk to me or I'm out of here

OpenStudy (anonymous):

i really dont know im new to chem

OpenStudy (jamesj):

The basic rule is the number of atoms of each type of atom must equal on both sides of the reaction. You have this reaction ___ Mg + ____ AlCl3----> ____ Al + _____ MgCl3 you have magnesium Mg, Aluminum Al, and Chlorine Cl atoms. There must be an equal number of both on both sides of the reaction. In other words, we have to fill in the blanks so that's true.

OpenStudy (jamesj):

So let's start with a guess: 1 Mg on the left hand side, LHS: 1 Mg + ____ AlCl3----> ____ Al + _____ MgCl3 Now, that being the case, how many MgCl3 molecules must we have on the right hand side, RHS?

OpenStudy (jamesj):

@2b, please don't give the answer, yet! ;-)

OpenStudy (anonymous):

being funny or really

OpenStudy (2bornot2b):

The equation is balanced, and I think you should write it differently

OpenStudy (2bornot2b):

I mean the last term should be Mgcl2

OpenStudy (jamesj):

1 Mg + ____ AlCl3----> ____ Al + _____ MgCl3 Now, that being the case, how many MgCl3 molecules must we have on the right hand side, RHS? There can only be 1 MgCl3 molecule on the RHS, because there's only one Mg atom from the LHS. Hence we must have 1 Mg + ____ AlCl3----> ____ Al + 1 MgCl3 Now ask yourself: how many Cl atoms are there on the RHS and hence how many must there be on the LHS?

OpenStudy (jamesj):

Oh ... sdig, did you give us the wrong equation?

OpenStudy (jamesj):

Figure that out and repost the question. The site is going down in a minute anyway.

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