Question

How do I put in the vertex form this equation?
Y=x^2 -6X+8

Answer 1

\[y=x^2-6x+8\] first coordiante of the vertex is
\[-\frac{b}{2a}=-\frac{-6}{2\times1}=3\]

Answer 2

second coordinate is what you get when you replace x by 3, namely
\[y=3^2-6\times 3+8=9-18+8=-9+8=-1\]

Answer 3

so since vertex is
\[(3,-1)\]
vertex form is
\[y=(x-3)^2-1\]

Answer 4

Thank you satellite

Answer 5

yw