Please help. i have a test today and I'm not understand some of these problems. The line passes through (-6,1) and is perpendicular to the line whose equation is x+3y=9 (thank you:))

Question

Please help. i have a test today and I'm not understand some of these problems.  The line passes through (-6,1) and is perpendicular to the line whose equation is x+3y=9  (thank you:))

anonymous · Answer

i got y=1/3x+3 but the answer is y=3x+19

anonymous · Answer

do you know what the slope of the line 
$$x+3y=9$$ is?  that is the first step to finding the answer

anonymous · Answer

oh I'm sorry, i forgot to write that...it's -2

anonymous · Answer

actually it is 
$$-\frac{1}{3}$$

anonymous · Answer

$$ax+by=c$$ slope is 
$$-\frac{a}{b}$$

anonymous · Answer

im sorry...yes, youre right..i was looking at a different problem (so out of it)

anonymous · Answer

so since the slope is 
$$-\frac{1}{3}$$ perpendicular line will have slope 3

anonymous · Answer

that should get you started for the right answer

anonymous · Answer

and now i use point slope form with the -1/3 as the slope part?

anonymous · Answer

wait, dont i have to change the x+3y=9 to slope intercept form?