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Mathematics 9 Online
OpenStudy (anonymous):

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to y from the second equation is substituted into the first equation. 2x – 5y = –3 6x – 3y = –3

OpenStudy (anonymous):

Step 1: Take \(6x-3y=-3\), and rewrite it in the form \(y=something\). What do you get?

OpenStudy (anonymous):

i got y= 6x+3

OpenStudy (anonymous):

I'm afraid I got a different answer. Could you post your steps?

OpenStudy (anonymous):

i just guessed.

OpenStudy (anonymous):

Try working it out :P

OpenStudy (anonymous):

uh i don't know how

OpenStudy (anonymous):

Alrighty, start with \[6x-3y=-3\]Your goal is to get y on its own, on one side of the equation. The first step then should be to add and subtract things from both sides until you get all the ys on one side: |dw:1326232364759:dw|

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