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OpenStudy (anonymous):

what is the mass in grams of 9456 molecules of Na2HPO4?

OpenStudy (anonymous):

find me the molar mass of this and i will set up the factor label for you

OpenStudy (anonymous):

5.6*10^27

OpenStudy (anonymous):

That number is too big to be the molar mass, to find molar mass add up the indivual atoms atomic weight in the molecule

OpenStudy (anonymous):

0o umm 141.96

OpenStudy (anonymous):

\[9456 Na_2HPO_4 atoms (\frac{1 moleNa_2HPO_4 }{6.022x10^23Na_2HPO_4 atoms })(\frac{141.96 g }{1 mole})=2.229x10^-18 g \]

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