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5. Solve, the following system of equations by linear combination: 2d + e = 8 d -e = 4
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2d +e =8 d-e=4 then d=4+e substitute 2(4+e)+e=8 8+2e+e=8 3e=0 e=0 so d=4
2d+e=8 d-e=4 --------- d= 4
is that how you do this?
i kinda for got how do do combinations they dont pop up too much
i know me too!
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The solution is (5, 2). The solution is (4, 0). There is no solution. There are an infinite number of solutions.
:)
those are the choices
if you are saying that there are an infinite number of sol then there is a sol
just many
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the answer no sol. would be incorrect if that was answered on a test question
ohh ok thanks
well gtg now sleep
bye bye now
night!
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:)
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