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Mathematics 18 Online
OpenStudy (anonymous):

3x/x+2 > 5

OpenStudy (king):

x>-5

OpenStudy (anonymous):

isnt it supposed to be < ?

myininaya (myininaya):

\[\frac{3x}{x+2} >5 ?\]

OpenStudy (king):

3x/x+2>5 3x>5x+10 -2x>10 x>-5

OpenStudy (anonymous):

i think its x<-5

OpenStudy (king):

if x<-5 then suppose x is -6 then substitute and u will get -18/-4 that is 4.5 which is not greater than 5

OpenStudy (anonymous):

since youve divided it with negative.

OpenStudy (king):

ya so , 10/-2=-10/2=-5

OpenStudy (king):

no!-5 is lesser than -4!

OpenStudy (anonymous):

what t tough question @@@@@@@@@@@

OpenStudy (king):

its -2>x>-5

OpenStudy (king):

that is x should be lesser than -2 but greater than -5 that is it can be -3 or -4

myininaya (myininaya):

\[\frac{3x}{x+2}-5 > 0 \] \[\frac{3x}{x+2}-\frac{5(x+2)}{x+2}>0\] forgot to multiply top to by (x+2) my bad \[\frac{-2x-10}{x+2} >0\] undefined at x=-2 and zero at x=5 use these numbers to test around ----|-----|----- -2 5 You have 3 intervals to check if I have right problem. lol

myininaya (myininaya):

or i mean x=-5

OpenStudy (king):

myininaya what do u mean by 'You have 3 intervals to check if I have right problem'?

myininaya (myininaya):

undefined at x=-2 and zero at x=-5 use these numbers to test around ----|-----|----- -5 -2 You have 3 intervals to check if I have right problem.

myininaya (myininaya):

well no one ever told me i had the right the problem above

myininaya (myininaya):

she wrote 3x/x+2>5 not 3x/(x+2)>5

myininaya (myininaya):

i assumed it was the second because it made more sense

OpenStudy (anonymous):

It must be the second, the first one makes no sense.

OpenStudy (king):

the other is not possible!

myininaya (myininaya):

exactly

myininaya (myininaya):

lol

OpenStudy (king):

3x/x=3 so 3+2=5 5>5! not possible!

myininaya (myininaya):

thats why i assumed the second one

OpenStudy (anonymous):

so which one is the correct answer?

OpenStudy (anonymous):

My approach, I used the idea that for \( \large \frac{3x}{x+2} \gt 5 \) both the numerator and denominator must be of same sign, these gives me 5 in inequalities, and the intersection of which is \( -5<x<-2 \) and this is the required answer to this problem.

OpenStudy (anonymous):

@jesscasama got the answer?

OpenStudy (anonymous):

YAH

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