Question

quadratic equation

2x^2 - 8x = -7.

Answer 1

yes it is

Answer 2

...

Answer 3

it is a quad eq; what are you spose to do with it?

Answer 4

i can't figure this one out

Answer 5

me either ...

what is it that we are trying to figure out?

Answer 6

the answer is going to be
-2 \[\pm\] sqrt 2
-2 \[\pm\] 2 sqrt 2
-2 \[\pm\] sqrt 2
----------------
2
-2 \[\pm\] sqrt 2/2

Answer 7

that came out bad

Answer 8

oh, you want to know the x intercepts

Answer 9

yes

Answer 10

using what method? complete square, quad formula, or other?

Answer 11

quadratic formula
ax^2 + bx+ c = 0
then
-b +or- sqrt b^2 -4ac
-------------------
2a

Answer 12

complete the square

2x^2 - 8x = -7

2(x^2 - 4x) = -7

2(x^2 -4x +4 - 4) = -7

2(x^2 -4x +4) - 2(4) = -7

2(x -2)^2 - 8 = -7

2(x -2)^2 = -7 + 8

(x -2)^2 = 1/2

x-2 = +- sqrt(1/2)

x =2 +- sqrt(1/2)

Answer 13

\[ax^2 + bx + c=0\]
\[x=\frac{1}{2a}(-b\pm\sqrt{b^2-4ac})\]

Answer 14

2x^2 -8x +7 = 0

\[x=\frac{1}{2.2}(--8\pm\sqrt{(-8)^2-4.2.7})\]

\[x=\frac{1}{4}(8\pm\sqrt{64-56})\]

\[x=\frac{1}{4}(8\pm\sqrt{8})\]

\[x=\frac{1}{4}(8\pm\sqrt{4.2})\]

\[x=\frac{1}{4}(8\pm\sqrt{4}\ \sqrt{2})\]

\[x=\frac{1}{4}(8\pm2\sqrt{2})\]

Answer 15

thanks

Answer 16

yep