Question

please solve in radians from start to finish, even if u won't explain, please show working. 7sec(3t)=-10

Answer 1

Divide both by 7.

Answer 2

Then, do what sec does. (Reverse of whatever is it). This should the right side -1/70 after 2 steps.

Answer 3

After, divide both sides by 3

Answer 4

I was incredibly vague in step 2. IF you'd like me to refine that, tell me. But I am busy.

Answer 5

Is sec 1/cos?

Answer 6

yes

Answer 7

1. Divide both sides by 7.
2.sec3t=-10/7
3.1/cos3t=-10/7
4. cos3t=7/-10
5.cos3t/3=(7/-10)/3
6.t=cos^-1[(7/-10)/3
DERONE!

Answer 8

HOOAH

Answer 9

sec(3t)=-10/7
cos(3t)=-7/10
3t = 2.346 +2pi=8.629 +2pi=14.912
t=.782, 2.876,4.971
3t = 3.937 +2pi=10.220+2pi=16.503
t=1.312,3.407,5.501

Answer 10

AWw. Sigh.

Answer 11

5.cos3t/3=(7/-10)/3
YOU CAN'T DO THAT!!!!

Answer 12

Mertsj's answers are the same as that in my book... i guess i was on the right path... i got stuck after getting the angle 3t.... since that was the angle, i wasn't sure if i had to continue to find t or they just needed the angle. thanks a ton :)

Answer 13

That's why I failed that test.

Answer 14

Eroops.