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Mathematics 22 Online
OpenStudy (anonymous):

How many combinations of four can you make from the set? a rose, a daisy, a peony, a daffodil, a tulip I figured since this is a combination, I would do 5C4, but I wasn't sure. Can someone give me some assurance on that? Thank you.

OpenStudy (amistre64):

5c4 is good

OpenStudy (anonymous):

Okay. Thank you.

OpenStudy (amistre64):

does order count? is rose daisy different or same as daisy rose?

OpenStudy (slaaibak):

^ should be.

OpenStudy (anonymous):

It doesn't say order counts, but it put them in that order, so I don't know.

OpenStudy (slaaibak):

5C4 is correct

OpenStudy (anonymous):

Do you guys still think 5C4?

OpenStudy (amistre64):

combonation tends to mean order counts

OpenStudy (anonymous):

okay.

OpenStudy (amistre64):

if I have a lock, 4-13-6 is a different combonation than 13-6-4

OpenStudy (anonymous):

True.

OpenStudy (anonymous):

So, you work with the order they gave you? Therefore it's 5.

OpenStudy (anonymous):

5C4*

OpenStudy (amistre64):

id vote for it being a ambiguious question :)

OpenStudy (anonymous):

Oh, and while I'm here, does "arrangement" have more to do with combinations or permutations?

OpenStudy (anonymous):

unless the girl cares about which flower comes first, i'd say its 5c4 ;)

OpenStudy (amistre64):

how many ways can you permutate me and you? 1 way. how many ways can you and me stand in a row? 2 ways

OpenStudy (anonymous):

So, combination!

OpenStudy (amistre64):

combo is what im thinking as well

OpenStudy (anonymous):

Okay, because that is on another of my questions.

OpenStudy (anonymous):

Thanks, guys.

OpenStudy (amistre64):

i reserve the right to be wrong tho :)

OpenStudy (anonymous):

I may need help with this.

OpenStudy (anonymous):

Seven skiers enter a downhill race. First, second, and third places will be given to the three fastest skiers. How many arrangements of first, second, and third places are possible with seven skiers?

OpenStudy (anonymous):

Maybe 7P3?

OpenStudy (amistre64):

just for a memory check 4c0 4c1 4c2 4c3 4c4 1 4 6 4 1 4p0 4p1 4p2 4p3 4p4 1 4 12 24 24 does that sound right?

OpenStudy (anonymous):

Yeah.

OpenStudy (amistre64):

1st 2nd 3rd 7 * 6 * 5

OpenStudy (anonymous):

So it is permutation, and 7P3?

OpenStudy (amistre64):

7p3 for the skiers, yes

OpenStudy (anonymous):

Alright, thank you for you help.

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