is (-1,-1) (1,3) equal 3--1 over 1--1 = 4/2 = 2?
\[\left[\begin{matrix}3 & +1 \\ 1& +1\end{matrix}\right] = \left(\begin{matrix}4 \\ 2\end{matrix}\right)\]
which equals 2
you mean slope right?
he got me confused here!!
its just those y2-y1 over x2-x1 equations
(-1,-1) (1,3) represents 2 points on a graph right?
wait.. let me rephrase.. forget everything i said.. Write the equation of the line through the points (-1,-1), (1,3)
ok! now what you worked out is the slope the line = 2 now you use the standard equation y-y1 = m(x-x1) where m = slope and (x1,y1) is a point on the line we can use any of the two points in your question lets use (1,3) x1 = 1 and y1 = 3 we get: y - 3 = 2(x-1) y - 3 = 2x - 2 y = 2x + 1 - theres the equation of your line
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