Zarkon can u plz come help me?
ok this is the correct one
i would use 0,1,2,3 for 1920,1930,1940,1950 that will make the numbers smaller
then for 1960 you can evaluate your function at 4
if you let \[f(x)=a+bx+cx^2+dx^3\] then solve the system \[f(0)=106\] \[f(1)=123\] \[f(2)=132\] \[f(3)=151\] for a,b,c,d
I get 106,27,-13,3
right but i landed up with an inconsistent system
I did not ;)
lol
write out the full equations I wrote above
oh i may have gone wrong since i made my point sthe following
(0,106)(10,123)(20,132)(30,151) these r my points
that would work too
you will get a different polynomial ...but the same final answer
neways i think i will use ur values isnce they r easier to work with :D
shld i write out the equations? or the matrix?
either
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