A 2kg block is taken from a furnace where its temperature was 650C and placed on a large block of ice at 0C .Assuming that all the heat given up by the iron is used to melt the ice,how much ice is melted.
Still here? (Heat released by 2kg block of iron as it goes from 650 C to 0 C) = (Heat used by water x kg water to go from solid to liquid) Now figure out how to write down both sides of that equation.
Hello Sonia. I am being an electronic engineering. About 1 year I didn't touch heat chapter or you can say classical mechanics. If you move some steps forward then I can help you in this. Is this specific heat question?
Yes, clearly it is. Let \( c_{iron} \) be the specific heat of iron in units of Joules/(gram.Kelvin). The the amount of heat energy of 2 kg, \( m_{iron} = 2000 g \) moving from temperature T = 650 C to 0 C, \( \Delta T = 650 K \) is \[ \Delta T . c . m_{iron} \] Now find the formula for the heat required to melt x grams of ice and set it equal to this one.
Correct.
yes, I know, many thanks.
Join our real-time social learning platform and learn together with your friends!