what will be the pH of solution when two buffer of pH 4 and 6 mixed each other.

Question

trancenova · Answer

Well, if pH 7 is neutral, and 6 and 4 are both equally apart from 7 (and assuming you add the same amount of each buffer), what do you think? :)

anonymous · Answer

1) $$10^{-4}+10^{-6} = 1.01*10^{-4}$$

anonymous · Answer

your volume doubled, therefore, (1.01*10^{-4})/2 = 5.05*10^{-5}

anonymous · Answer

pH = -log (5.05 x 10^-5) = 4.30

anonymous · Answer

I think you can not tell just by the facts you gave us. for example:

if the buffer capacity of the pH 6 solution is used up, but the pH 4 buffer is still able to compensate for the change, the pH will be close to 4, and vice versa. you need to give concentrations of HA / A- for each buffer solution.

anonymous · Answer

lol @ trancenova, btw =) 6 and 4 being equally apart from 7, nice

anonymous · Answer

@Schleifspur: yes, thank you, my mistake, I assumed that the volumes of the buffers would be the same, but that is not clear from the question. Thanks for catching!!!!

blues · Answer

You'd need to know the concentrations of both buffers.

anonymous · Answer

@ blues: pH already shows molar concentration of H30+ ions

blues · Answer

Oh, didn't notice that.