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Mathematics 12 Online
OpenStudy (anonymous):

simplify 6/√14

OpenStudy (akshay_budhkar):

\[{6 \over \sqrt14}= {6 \over \sqrt 14} \times { \sqrt 14 \over \sqrt 14} = {{6 \times \sqrt14} \over 14}={{3\times \sqrt 14} \over 7}\]

OpenStudy (anonymous):

rationalize the denominator

OpenStudy (anonymous):

exactly what akhsay showed you

OpenStudy (akshay_budhkar):

i am always exact :P :P jkjk

OpenStudy (anonymous):

Thanks guys(:

OpenStudy (akshay_budhkar):

no one is a loser :D

OpenStudy (radar):

\[6\over \sqrt{14}\]multiply both numerator and denominator by\[\sqrt{14}\]getting\[6\sqrt{14}\over \sqrt{14}\sqrt{14}\]getting \[3\sqrt{14}\over7\]

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