if rect(t) is function between -1/2 to 1/2

would rect(t/4) be stretched or shrunk?

Question

if rect(t) is function between -1/2 to 1/2

would rect(t/4) be stretched or shrunk?

anonymous · Answer

why

anonymous · Answer

lol btw what do you mean by stretch and shrunk?

akshay_budhkar · Answer

ok if we take sinx and sinx/4 , it lies between -1 and 1

akshay_budhkar · Answer

so i beliueve it wont change

anonymous · Answer

it would stretch

akshay_budhkar · Answer

Why?

anonymous · Answer

ishaan, that's what I am thinking too

anonymous · Answer

u=t/4

             -1/2<u<1/2
             -1/2<t/4<1/2

akshay_budhkar · Answer

but u aren't provided with the function

asnaseer · Answer

It would stretch in the horizontal direction - not the vertical direction. @Akshay Budhkar is correct in that sense.

anonymous · Answer

-2<t<2

anonymous · Answer

I meant the period

akshay_budhkar · Answer

-_-

akshay_budhkar · Answer

the period stretches !

anonymous · Answer

lol what else were you thinking? akshay

anonymous · Answer

I think he was thinking amplitude

asnaseer · Answer

@imranmeah91 - there is nothing in the question to indicate that rect is a periodic function

anonymous · Answer

oh amplitude 

"if rect(t) is function between -1/2 to 1/2 "
i think this lines suggests it's periodic nature

anonymous · Answer

line*

anonymous · Answer

ok, horizontally stretched

asnaseer · Answer

|dw:1326849951351:dw|
one possibility is it could asymptote towards the two limits