Mathematics
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OpenStudy (anonymous):
if rect(t) is function between -1/2 to 1/2
would rect(t/4) be stretched or shrunk?
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OpenStudy (anonymous):
why
OpenStudy (anonymous):
lol btw what do you mean by stretch and shrunk?
OpenStudy (akshay_budhkar):
ok if we take sinx and sinx/4 , it lies between -1 and 1
OpenStudy (akshay_budhkar):
so i beliueve it wont change
OpenStudy (anonymous):
it would stretch
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OpenStudy (akshay_budhkar):
Why?
OpenStudy (anonymous):
ishaan, that's what I am thinking too
OpenStudy (anonymous):
u=t/4
-1/2<u<1/2
-1/2<t/4<1/2
OpenStudy (akshay_budhkar):
but u aren't provided with the function
OpenStudy (asnaseer):
It would stretch in the horizontal direction - not the vertical direction. @Akshay Budhkar is correct in that sense.
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OpenStudy (anonymous):
-2<t<2
OpenStudy (anonymous):
I meant the period
OpenStudy (akshay_budhkar):
-_-
OpenStudy (akshay_budhkar):
the period stretches !
OpenStudy (anonymous):
lol what else were you thinking? akshay
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OpenStudy (anonymous):
I think he was thinking amplitude
OpenStudy (asnaseer):
@imranmeah91 - there is nothing in the question to indicate that rect is a periodic function
OpenStudy (anonymous):
oh amplitude
"if rect(t) is function between -1/2 to 1/2 "
i think this lines suggests it's periodic nature
OpenStudy (anonymous):
line*
OpenStudy (anonymous):
ok, horizontally stretched
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OpenStudy (asnaseer):
|dw:1326849951351:dw|
one possibility is it could asymptote towards the two limits