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factor the four term polynomial by grouping x^3+6x^2+8x+48
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\[x^3+6x^2+8x+48=x^2(x+6)+8(x+6)=(x^2+8)(x+6)\]
do you get it?
no not really can u help me?
ok in the first two term i took x^2 common, in the next two terms i took 8 common.. Do you get that part?
yes
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ok in the thrid part i take (x+6) common.. so that is how i get that product
but where do u get (x-6) from?
it is x+6
i took it common no.. see the first two terms are\[x^3+6x^2\] so taking x^2 common i have\[x^2(x+6)\]
you get it?
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yes i do now
so is the entire question clear or are u still unclear in some part?
no i get it now thanks
ok happy that you get it =D
okay wait one more question so how did u end up with (x^2+8)(x+6)
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