Question

(please show steps) solve the inequality: 1/x <(or equal to) 1/x+1

Answer 1

OK, well, how do you solve an equation with a variable in the denominator?

Answer 2

muahah. yay. actual not answering.

Answer 3

\[1/x \le 1/x+1\]times all terms by x
\[1 \le 1+x\]solve for x
\[0 \le x\]\[x \ge 0\]

Answer 4

is that a 1/x +1 or a 1/(x+1) ?

Answer 5

(x+1)

Answer 6

1/x-1/(x+1)<0 taking LCM you get 1/(x(x+1))<0 , This means -1<=x<=0

Answer 7

Remember never cancel x on both sides of the inequality even if you get it common, take it the other side and factorize. (If x is negative the inequality is reversed on cancelling x n both sides)