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Mathematics 13 Online
OpenStudy (anonymous):

Is this differential equation homogeneuos? F(x,y,y',y'')=0 And how would look like nonhomogeneuos DE in this form?

OpenStudy (anonymous):

Yes, a homogenous equation is equal to 0

OpenStudy (anonymous):

and how would look like nonhomogeneuos?

OpenStudy (anonymous):

a non-homogenous equation would equal some function of x or a constant

OpenStudy (anonymous):

Ehhhh I'd be careful with this... F(x,y,y',y'') = y'' + y' + y + sin(x) = 0 is not homogeneous...

OpenStudy (anonymous):

i know, but im interesting in this form....F(x,y',y'',..)=0....you have x here,maybe this is a constant?

OpenStudy (anonymous):

ahh good point Jemurray3 i missed the x in there.

OpenStudy (anonymous):

so, from this for you can only see its second order?

OpenStudy (anonymous):

The definition for a homogeneous second order differential that I always would fall back on is something of the form \[ a(x) y''(x) + b(x) y'(x) + c(x) y(x) = 0\]

OpenStudy (anonymous):

differential equation*

OpenStudy (anonymous):

Just so long as every term involves y or one of its derivatives, really.

OpenStudy (anonymous):

but from this form you cant conclude if its homogeneuos or not?

OpenStudy (anonymous):

F(x,y,y',y'') = 0 defines a second order, ordinary differential equation. That is all the information you can get from that.

OpenStudy (anonymous):

ok, thanks

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