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anti-derivative (1)/x^2dx
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\[\int x^{-2}\ dx\]
to derive a power we multiply and subtract 1, to undo that we add 1 and divide
So would my answer be (-1/3x^3)?
it would; +C
opps, read it wrong: -1/3 x^-3
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+C ....
\[\int x^{-2}\ dx=-\frac{1}{1}x^{-1}=-\frac{1}{x}+C\] thats better
okay thanks. I need to know how to type another problem but I do not know how to type it in integral notation. COuld you explain how to do that please?
I gotta get to class at the moment; but good luck :)
ok well later Thanks. :)
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use the power rule backwards
\[\frac{d}{dx}x^n=nx^{n-1}\] \[\int x^n dx=\frac{x^{n+1}}{n+1}\]
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